3x^(1/2)-7x^(1/4)-6=0

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Solution for 3x^(1/2)-7x^(1/4)-6=0 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

3*x^(1/2)-(7*x^(1/4))-6 = 0

3*x^(1/2)-7*x^(1/4)-6 = 0

t_1 = x^(1/4)

3*t_1^2-7*t_1^1-6 = 0

3*t_1^2-7*t_1-6 = 0

DELTA = (-7)^2-(-6*3*4)

DELTA = 121

DELTA > 0

t_1 = (121^(1/2)+7)/(2*3) or t_1 = (7-121^(1/2))/(2*3)

t_1 = 3 or t_1 = -2/3

t_1 = -2/3

x^(1/4)+2/3 = 0

1*x^(1/4) = -2/3 // : 1

x^(1/4) = -2/3

( -2/3 < 0 i 1/4 in (0:1) ) => x należy do O

t_1 = 3

x^(1/4)-3 = 0

1*x^(1/4) = 3 // : 1

x^(1/4) = 3

x^(1/4) = 3 // ^ 4

x = 81

x = 81

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